11025=2x^2

Solution for 11025=2x^2 equation:

11025=2x^2

We move all terms to the left:

11025-(2x^2)=0

a = -2; b = 0; c = +11025;
Δ = b2-4ac
Δ = 02-4·(-2)·11025
Δ = 88200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{88200}=\sqrt{44100*2}=\sqrt{44100}*\sqrt{2}=210\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210\sqrt{2}}{2*-2}=\frac{0-210\sqrt{2}}{-4}
=-\frac{210\sqrt{2}}{-4}
=-\frac{105\sqrt{2}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210\sqrt{2}}{2*-2}=\frac{0+210\sqrt{2}}{-4}
=\frac{210\sqrt{2}}{-4}
=\frac{105\sqrt{2}}{-2}
$